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Ask community Community Discussion Question: Find values of x: (x^3-1)/x>=0
Reply Forum Index -> Algebra originally posted here on IIT-JEE / AIEEE community   
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Apurva Rai (0)

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Find values of x: (x^3-1)/x>=0
    
Sujit (1994)

Olaaa!! Perrrfect answer. 318  [520 rates]

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 for all values of x greater or equal to 1

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HIMANSHU JAIN (376)

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it can be solved as:

((x-1)*(x^2+x+1))/x >=0

now, x^2+x+1 is always greater than 0.

so, we are just to check (x-1)/x >=0

=> x not equal to 0.

and (x-1) >=0

hance, ans is x>=1

 


Himanshu Jain
P.E.C.
http://jainhim.blogspot.com/
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