|
Author
|
Message
|
![[Post New]](/templates/default/images/icon_minipost_new.gif)
2 Jan 2011 16:07:42 IST
|
|
|
IF 1+3+5+7+9+11+13+15+17+19=100 HOTE HAIN TO INME SE WO 5 NO. KOUN SE HAIN JINKA TOTAL 50 MILEGA. PLZ SOLVE THIS...........
|
|
|
|
2 Jan 2011 16:52:37 IST
|
|
|
Its impossible to add anyone of these 5 odd numbers and get 50 because you can't get an even number by adding an odd number odd times. See you have got 100 by adding the odd numbers even times i.e. 10 times but that doesn't imply that you'll get its half by adding half the number of times i.e. 5 times. You can get 50, by adding 4 and 6 odd numbers for e.g 1+5+7+9+11+17= 50, unless there is no even number given, you can't get 50 as the answer and such type of questions I think don't come in IIT JEE or other exams, but you can improve your IQ through such kind of questions.
|
this reply:
0 points
(with 0
in
0
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
2 Jan 2011 17:25:42 IST
|
|
|
no chances of adding any five of them and getting 50 as all are odd numbers and the sum cant be equal to 50
|
this reply:
0 points
(with 0
in
0
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
9 Aug 2011 19:56:52 IST
|
|
|
IF 1+3+5+7+9+11+13+15+17+19=100 HOTE HAIN TO INME SE WO 5 NO. KOUN SE HAIN JINKA TOTAL 50 MILEGA. PL
|
this reply:
0 points
(with 0
in
0
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
9 Aug 2011 20:34:27 IST
|
|
|
-12= -12=>9-21=16-28 =>3^2-(7*3)=4^2-(7*4) =>3^2-1/2(2*7*3)+(7/2)^2=4^2-1/2(2*7*4)+(7/2)^2 =>(3-7/2)^2=(4-7/2)^2 =>3-7/2=4-7/2 =>3=4.............(1) from the above equation(1) i.e 3=4 & 3-1=4-1=>2=3
hence 9+11+13+15+3=9+11+13+15+2 (as 2=3 )
|
this reply:
0 points
(with 0
in
0
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
3 Feb 2012 11:43:53 IST
|
|
|
IF 1+3+5+7+9+11+13+15+17+19=100 HOTE HAIN TO INME SE WO 5 NO. KOUN SE HAIN JINKA TOTAL 50 MILEGA. PL
|
this reply:
0 points
(with 0
in
0
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
5 Feb 2012 09:51:21 IST
|
|
|
15/3+19+17+11
|
this reply:
0 points
(with 0
in
0
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
5 Feb 2012 17:57:41 IST
|
|
|
Even number of 'odd numbrs' cn giv even numbr like 50. . . .bt 5 such n0s.cnt giv as '5' is odd. . .if u c0nsider th numbrs as x1+1,x2+1 . . .x5+ 1 whr x1,x2,x3,x4,x5 are evn,add them up,al x terms wil giv X,say,even numbr. .so X can n0t b 45 and remain 5*1 wil giv 5 and th t0tal sum wil b 50 had u get X=45
|
this reply:
0 points
(with 0
in
0
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
8 Mar 2012 23:50:55 IST
|
|
|
1+3+5+5+17+19=50
|
this reply:
0 points
(with 0
in
0
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
9 Mar 2012 00:14:23 IST
|
|
|
odd plus odd is even. in ur que. adding 10 odd numbers gives u an even number 100. but now u r asking to add fgive odd number. all the 10 no r odd so if 5 oddps r chosemn and added it will give odd no result but 50 is even. so no pops.
|
this reply:
0 points
(with 0
in
0
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
|
|
Moderation Team
Community Discussion Question:
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
