| Message |
|
|
|
see, it's parameteric in t. So, we need to differentiate it w.r.t "t". so, dx/dy = (dx/dt)/(dy/dt). But are u clear about the thing that w.r.t what you want to integrate it? means w.r.t. t?? so, first find dx/dy and then perform the integration accordingly w.r.t. the variable you want to do it. Do post again or nudge me if there's any doubt.
|
|
|
|
|
Arihant's Differential calculus is best book. You'll get to know most beautiful problems there. Go through it thoroughly. I found the quality of quns entirely different from other books. Best of luck :)
|
|
|
|
|
since we have 6 digits and we have to make 6 digit numbers. So, it's simply 6!. but point to note is that we have replication of digits. So, we have 6!/(2!*2!*2!) = 90
|
|
|
|
|
but in your case, x1..x5 will not remain integer. They all need to be integer, so how there powers can be reduced less than 1. We are asked integral solution, so all x1..x5 need to be integers.
|
|
|
|
|
S.L. Loney is definitely the first choice. Arihant trigo by Amit M. Aggarwal is also a good book.
|
|
|
|
|
first thing to observe is: there can be atmost n boxes used.. So, we'll start with 1 box : we'll have to put all the balls into it. if we have 2 boxes then we can make cases for it like 2 in first and (n-2) in 2nd like this. we'll have to continue this till n boxes, in which in the end, each box will have one ball.. Hope it's cleared. I have posted a logical solution. So, figure out and if still there's any doubt then post again. :)
|
|
|
|
|
well, if it's computer related stuff.. So, I can help you. www.jainhim.blogspot.com Also, you can post whatever you need to know; Regarding tutorials, you can try : http://www.nptel.iitm.ac.in/courses.php
|
|
|
|
|
just visit this link: http://www.nptel.iitm.ac.in/courses.php?branch=Comp you'll get whatever you need.
|
|
|
|
|
|
see it's very easy to analyze: first find it's factors: 1050 = 2*3*5*5*7 Now, as we can change the values between different xs. Soo, we get ans: 5! but we have two 5s. That's why, ans is 5!/2! = 60.
|
|
|
|
|
it's very easy to analyze: 1) either u can use the formulas written in maths ncert 2) use exact form i m giving sol using exact form: ydx + xdy = - ( x^2 dy) => d(xy) = - (((xy)^2)/y)dy => (1/((xy)^2)) = - (1/y) dy on integrating: => -(1/(xy)) = - (ln y) +c
|
|
|
|
|
Store the number in a string. Reverse the string. And just compare the two strings. If they are equal then number is palindrome.. Do post again if ther's any doubt.
|
|
|
|
|
the answer is infinity. Although the value above will be come -Sin 1, but the denomintor will always be very-very less than Sin1.
|
|
|
|
|
It is exactly same as: 0*2 = 0 *15 so, cancelling 0s on both sides, u get 2=15. I hope you know now where the mistake lies.
|
|
|
|
|
I would suggest first take a paper and write down all the theorems you have studied starting from class 7th and then go through very carefully the theory of each section. Also, do have a note about circumcentre, incentre, orthocentre etc.
|
|
|
|
|
2nd solution: Assume all the three co-ordinates as mentioned just above. and then you can use: Tan60 = mode of ((m1-m2)/(1-m1*m2)). m1,m2 are slopes. 3rd solution: Assume centroid to be (h,k) and take one point to be (aCos@, bSin@). now, find the equation of line from these two points. Now, rotate this line 120 and -120 degree and find the two more intersection points with ellipse. After that you can just equate the lengths of the side to get the desired result. I hope it's clear now..
|
|
|
|
|
|
It is zero. look, it this way: derivative: Cos(x^0) multiplied by derivative of x^0. which is zero. I hope I am clear..
|
|
|
|
|
Oh!! that was the wrong solution i posted. I am sorry for that. here's the correct one: assume cordinates as A(aCos@,bSin@), B(aCos$,bSin$) and C(aCos&, bSin&). Now, as you know all the sides of an equilateral triangle are equal. So, AB=AC, AC=BC and AB=BC. you'll get the values of all the three variables, since you have three equations. now, centroid of the triangle is (x1+x2+x3)/3, (y1+y2+y3)/3. @pranjali: I am considering it to be a general ellipse ((x/a)^2 +(y/b)^2)=1. Do post again if there's any doubt.
|
|
|
|
|
Well, I am not posting the whole solution. It'll be better if u try this qun yourself. I can tell you how to solve this. Assume co-ordinates A (aCos@,bSin@). Now, as it's an quilateral triangle,next co-ordinate will be B (aCos(@+120),bSin(@+120)) next will be C(aCos(@+24), bSin(@+240)) Now, you have co-ordinates of equilateral triangle and I think now you know what to do.. centroid is ((x1+x2+x3)/3,(y1+y2+y3)/3). Now, it's simple trigo. still if you have any doubt, you can ask. Try to do it yourself.
|
|
|
|
